21113120433 has 8 divisors (see below), whose sum is σ = 28234362208. Its totient is φ = 14033646144.

The previous prime is 21113120401. The next prime is 21113120459. The reversal of 21113120433 is 33402131112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 21113120433 - 2⁵ = 21113120401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21113120533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10440691 + ... + 10442712.

It is an arithmetic number, because the mean of its divisors is an integer number (3529295276).

Almost surely, 2^21113120433 is an apocalyptic number.

It is an amenable number.

21113120433 is a deficient number, since it is larger than the sum of its proper divisors (7121241775).

21113120433 is a wasteful number, since it uses less digits than its factorization.

21113120433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20883743.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 21113120433 its reverse (33402131112), we get a palindrome (54515251545).

The spelling of 21113120433 in words is "twenty-one billion, one hundred thirteen million, one hundred twenty thousand, four hundred thirty-three".