2111312140403 has 8 divisors (see below), whose sum is σ = 2119782798000. Its totient is φ = 2102841952000.

The previous prime is 2111312140351. The next prime is 2111312140417. The reversal of 2111312140403 is 3040412131112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2111312140403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2111312140703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11011451 + ... + 11201547.

It is an arithmetic number, because the mean of its divisors is an integer number (264972849750).

Almost surely, 2^{2111312140403} is an apocalyptic number.

2111312140403 is a deficient number, since it is larger than the sum of its proper divisors (8470657597).

2111312140403 is a wasteful number, since it uses less digits than its factorization.

2111312140403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 234597.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 2111312140403 its reverse (3040412131112), we get a palindrome (5151724271515).

The spelling of 2111312140403 in words is "two trillion, one hundred eleven billion, three hundred twelve million, one hundred forty thousand, four hundred three".