Base | Representation |
---|---|
bin | 10011101010011100… |
… | …001100110010000001 |
3 | 2000111102002010200222 |
4 | 103222130030302001 |
5 | 321214430130423 |
6 | 13411011352425 |
7 | 1345126434125 |
oct | 235234146201 |
9 | 60442063628 |
10 | 21113130113 |
11 | 8a548a2169 |
12 | 41128b2715 |
13 | 1cb61a4aca |
14 | 1044081585 |
15 | 8388473c8 |
hex | 4ea70cc81 |
21113130113 has 8 divisors (see below), whose sum is σ = 21798389760. Its totient is φ = 20435980320.
The previous prime is 21113130089. The next prime is 21113130131. The reversal of 21113130113 is 31103131112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 21113130113 - 230 = 20039388289 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21113130091 and 21113130100.
It is not an unprimeable number, because it can be changed into a prime (21113130173) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2022173 + ... + 2032586.
It is an arithmetic number, because the mean of its divisors is an integer number (2724798720).
Almost surely, 221113130113 is an apocalyptic number.
It is an amenable number.
21113130113 is a deficient number, since it is larger than the sum of its proper divisors (685259647).
21113130113 is a wasteful number, since it uses less digits than its factorization.
21113130113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4054927.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 21113130113 its reverse (31103131112), we get a palindrome (52216261225).
Subtracting 21113130113 from its reverse (31103131112), we obtain a palindrome (9990000999).
The spelling of 21113130113 in words is "twenty-one billion, one hundred thirteen million, one hundred thirty thousand, one hundred thirteen".
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