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2111313241 = 2638027807
BaseRepresentation
bin111110111011000…
…0001010101011001
312110010210211021201
41331312001111121
513310444010431
6545300434201
7103214603122
oct17566012531
95403724251
102111313241
11993865984
124ab0a8961
1327854c39b
14160593049
15c554e461
hex7dd81559

2111313241 has 4 divisors (see below), whose sum is σ = 2119341312. Its totient is φ = 2103285172.

The previous prime is 2111313229. The next prime is 2111313251. The reversal of 2111313241 is 1423131112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2111313241 - 25 = 2111313209 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2111313251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4013641 + ... + 4014166.

It is an arithmetic number, because the mean of its divisors is an integer number (529835328).

Almost surely, 22111313241 is an apocalyptic number.

It is an amenable number.

2111313241 is a deficient number, since it is larger than the sum of its proper divisors (8028071).

2111313241 is an equidigital number, since it uses as much as digits as its factorization.

2111313241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8028070.

The product of its digits is 144, while the sum is 19.

The square root of 2111313241 is about 45949.0287274933. The cubic root of 2111313241 is about 1282.8746510719.

Adding to 2111313241 its reverse (1423131112), we get a palindrome (3534444353).

The spelling of 2111313241 in words is "two billion, one hundred eleven million, three hundred thirteen thousand, two hundred forty-one".

Divisors: 1 263 8027807 2111313241