Base | Representation |
---|---|
bin | 10011101010011100… |
… | …001111001110001001 |
3 | 2000111102002122102001 |
4 | 103222130033032021 |
5 | 321214430440410 |
6 | 13411011511001 |
7 | 1345126505221 |
oct | 235234171611 |
9 | 60442078361 |
10 | 21113140105 |
11 | 8a548a9722 |
12 | 41128b8461 |
13 | 1cb61a9515 |
14 | 1044085081 |
15 | 83884a33a |
hex | 4ea70f389 |
21113140105 has 8 divisors (see below), whose sum is σ = 25337320200. Its totient is φ = 16889477376.
The previous prime is 21113140093. The next prime is 21113140151. The reversal of 21113140105 is 50104131112.
It can be written as a sum of positive squares in 4 ways, for example, as 1261457289 + 19851682816 = 35517^2 + 140896^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 21113140105 - 25 = 21113140073 is a prime.
It is a super-2 number, since 2×211131401052 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33040 + ... + 208129.
It is an arithmetic number, because the mean of its divisors is an integer number (3167165025).
Almost surely, 221113140105 is an apocalyptic number.
It is an amenable number.
21113140105 is a deficient number, since it is larger than the sum of its proper divisors (4224180095).
21113140105 is a wasteful number, since it uses less digits than its factorization.
21113140105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 258683.
The product of its (nonzero) digits is 120, while the sum is 19.
Adding to 21113140105 its reverse (50104131112), we get a palindrome (71217271217).
The spelling of 21113140105 in words is "twenty-one billion, one hundred thirteen million, one hundred forty thousand, one hundred five".
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