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2111324161 = 3168107231
BaseRepresentation
bin111110111011000…
…0100000000000001
312110010211101021011
41331312010000001
513310444333121
6545301000521
7103214650012
oct17566040001
95403741234
102111324161
11993873101
124ab0b3141
1327855434b
14160597009
15c55527e1
hex7dd84001

2111324161 has 4 divisors (see below), whose sum is σ = 2179431424. Its totient is φ = 2043216900.

The previous prime is 2111324147. The next prime is 2111324191. The reversal of 2111324161 is 1614231112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2111324161 - 29 = 2111323649 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2111324101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34053585 + ... + 34053646.

It is an arithmetic number, because the mean of its divisors is an integer number (544857856).

Almost surely, 22111324161 is an apocalyptic number.

It is an amenable number.

2111324161 is a deficient number, since it is larger than the sum of its proper divisors (68107263).

2111324161 is an equidigital number, since it uses as much as digits as its factorization.

2111324161 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68107262.

The product of its digits is 288, while the sum is 22.

The square root of 2111324161 is about 45949.1475546609. The cubic root of 2111324161 is about 1282.8768628023.

Adding to 2111324161 its reverse (1614231112), we get a palindrome (3725555273).

The spelling of 2111324161 in words is "two billion, one hundred eleven million, three hundred twenty-four thousand, one hundred sixty-one".

Divisors: 1 31 68107231 2111324161