Base | Representation |
---|---|
bin | 1001100110011110100101… |
… | …11101010101100111110001 |
3 | 2202202102010102111212101220 |
4 | 10303033102331111213301 |
5 | 10231410021202221140 |
6 | 112523152345015253 |
7 | 4306246226056506 |
oct | 463172275254761 |
9 | 82672112455356 |
10 | 21113303554545 |
11 | 6800113485504 |
12 | 244ba96784529 |
13 | ba1c8c304677 |
14 | 52dc6450b4ad |
15 | 26931374abd0 |
hex | 1333d2f559f1 |
21113303554545 has 16 divisors (see below), whose sum is σ = 33797518935552. Its totient is φ = 11255017479680.
The previous prime is 21113303554451. The next prime is 21113303554573. The reversal of 21113303554545 is 54545530331112.
It is not a de Polignac number, because 21113303554545 - 29 = 21113303554033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21113303554497 and 21113303554506.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 338160417 + ... + 338222846.
It is an arithmetic number, because the mean of its divisors is an integer number (2112344933472).
Almost surely, 221113303554545 is an apocalyptic number.
It is an amenable number.
21113303554545 is a deficient number, since it is larger than the sum of its proper divisors (12684215381007).
21113303554545 is a wasteful number, since it uses less digits than its factorization.
21113303554545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 676385352.
The product of its (nonzero) digits is 540000, while the sum is 42.
Adding to 21113303554545 its reverse (54545530331112), we get a palindrome (75658833885657).
The spelling of 21113303554545 in words is "twenty-one trillion, one hundred thirteen billion, three hundred three million, five hundred fifty-four thousand, five hundred forty-five".
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