21113440113 has 4 divisors (see below), whose sum is σ = 28151253488. Its totient is φ = 14075626740.

The previous prime is 21113440043. The next prime is 21113440121. The reversal of 21113440113 is 31104431112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 21113440113 - 2⁹ = 21113439601 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 21113440113.

It is not an unprimeable number, because it can be changed into a prime (21113440163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3518906683 + ... + 3518906688.

It is an arithmetic number, because the mean of its divisors is an integer number (7037813372).

Almost surely, 2^21113440113 is an apocalyptic number.

It is an amenable number.

21113440113 is a deficient number, since it is larger than the sum of its proper divisors (7037813375).

21113440113 is an equidigital number, since it uses as much as digits as its factorization.

21113440113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7037813374.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 21113440113 its reverse (31104431112), we get a palindrome (52217871225).

Subtracting 21113440113 from its reverse (31104431112), we obtain a palindrome (9990990999).

The spelling of 21113440113 in words is "twenty-one billion, one hundred thirteen million, four hundred forty thousand, one hundred thirteen".