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2111404433 = 67197347461
BaseRepresentation
bin111110111011001…
…0111100110010001
312110010222110101012
41331312113212101
513311004420213
6545302420305
7103215433025
oct17566274621
95403873335
102111404433
11993918446
124ab131695
13278581a48
141605b8385
15c556b4a8
hex7dd97991

2111404433 has 16 divisors (see below), whose sum is σ = 2164688064. Its totient is φ = 2058893760.

The previous prime is 2111404423. The next prime is 2111404441. The reversal of 2111404433 is 3344041112.

It is a cyclic number.

It is not a de Polignac number, because 2111404433 - 220 = 2110355857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2111404399 and 2111404408.

It is not an unprimeable number, because it can be changed into a prime (2111404423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4579823 + ... + 4580283.

It is an arithmetic number, because the mean of its divisors is an integer number (135293004).

Almost surely, 22111404433 is an apocalyptic number.

It is an amenable number.

2111404433 is a deficient number, since it is larger than the sum of its proper divisors (53283631).

2111404433 is a wasteful number, since it uses less digits than its factorization.

2111404433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1072.

The product of its (nonzero) digits is 1152, while the sum is 23.

The square root of 2111404433 is about 45950.0210337275. The cubic root of 2111404433 is about 1282.8931208121.

Adding to 2111404433 its reverse (3344041112), we get a palindrome (5455445545).

The spelling of 2111404433 in words is "two billion, one hundred eleven million, four hundred four thousand, four hundred thirty-three".

Divisors: 1 67 197 347 461 13199 23249 30887 68359 90817 159967 4580053 6084739 10717789 31513499 2111404433