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2111413003 = 71571191999
BaseRepresentation
bin111110111011001…
…1001101100001011
312110010222220010121
41331312121230023
513311010204003
6545302524111
7103215500020
oct17566315413
95403886117
102111413003
11993923927
124ab136637
1327858590b
141605bb547
15c556dcbd
hex7dd99b0b

2111413003 has 8 divisors (see below), whose sum is σ = 2414592000. Its totient is φ = 1808621160.

The previous prime is 2111413001. The next prime is 2111413021. The reversal of 2111413003 is 3003141112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2111413003 - 21 = 2111413001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2111413001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 85003 + ... + 106996.

It is an arithmetic number, because the mean of its divisors is an integer number (301824000).

Almost surely, 22111413003 is an apocalyptic number.

2111413003 is a deficient number, since it is larger than the sum of its proper divisors (303178997).

2111413003 is a wasteful number, since it uses less digits than its factorization.

2111413003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 193577.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 2111413003 is about 45950.1142871266. The cubic root of 2111413003 is about 1282.8948565256.

Adding to 2111413003 its reverse (3003141112), we get a palindrome (5114554115).

The spelling of 2111413003 in words is "two billion, one hundred eleven million, four hundred thirteen thousand, three".

Divisors: 1 7 1571 10997 191999 1343993 301630429 2111413003