Base | Representation |
---|---|
bin | 11110101110011010011… |
… | …100011110111100110011 |
3 | 21110211221111102101212101 |
4 | 132232122130132330303 |
5 | 234043142021203103 |
6 | 4253550100241231 |
7 | 305354646505645 |
oct | 36563234367463 |
9 | 7424844371771 |
10 | 2111420100403 |
11 | 7444a2669399 |
12 | 2a125a3a0217 |
13 | 12414c029a73 |
14 | 7429c4d8895 |
15 | 39dc9adaa1d |
hex | 1eb9a71ef33 |
2111420100403 has 4 divisors (see below), whose sum is σ = 2168485508560. Its totient is φ = 2054354692248.
The previous prime is 2111420100379. The next prime is 2111420100407. The reversal of 2111420100403 is 3040010241112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2111420100403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2111420100407) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28532704023 + ... + 28532704096.
It is an arithmetic number, because the mean of its divisors is an integer number (542121377140).
Almost surely, 22111420100403 is an apocalyptic number.
2111420100403 is a deficient number, since it is larger than the sum of its proper divisors (57065408157).
2111420100403 is an equidigital number, since it uses as much as digits as its factorization.
2111420100403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57065408156.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 2111420100403 its reverse (3040010241112), we get a palindrome (5151430341515).
The spelling of 2111420100403 in words is "two trillion, one hundred eleven billion, four hundred twenty million, one hundred thousand, four hundred three".
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