2111432240001 has 8 divisors (see below), whose sum is σ = 3217420556224. Its totient is φ = 1206532708560.

The previous prime is 2111432239999. The next prime is 2111432240009. The reversal of 2111432240001 is 1000422341112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2111432240001 - 2¹ = 2111432239999 is a prime.

It is a super-3 number, since 3×2111432240001³ (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (21), and also a Moran number because the ratio is a prime number: 100544392381 = 2111432240001 / (2 + 1 + 1 + 1 + 4 + 3 + 2 + 2 + 4 + 0 + 0 + 0 + 1).

It is a self number, because there is not a number n which added to its sum of digits gives 2111432240001.

It is not an unprimeable number, because it can be changed into a prime (2111432240009) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50272196170 + ... + 50272196211.

It is an arithmetic number, because the mean of its divisors is an integer number (402177569528).

Almost surely, 2^{2111432240001} is an apocalyptic number.

2111432240001 is a gapful number since it is divisible by the number (21) formed by its first and last digit.

It is an amenable number.

2111432240001 is a deficient number, since it is larger than the sum of its proper divisors (1105988316223).

2111432240001 is a wasteful number, since it uses less digits than its factorization.

2111432240001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100544392391.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 2111432240001 its reverse (1000422341112), we get a palindrome (3111854581113).

The spelling of 2111432240001 in words is "two trillion, one hundred eleven billion, four hundred thirty-two million, two hundred forty thousand, one".