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211210133113 = 7100692996611
BaseRepresentation
bin1100010010110100011…
…0101101111001111001
3202012011121010110011201
43010231012231321321
511430024243224423
6241010102054201
721154661336560
oct3045506557171
9665147113151
10211210133113
1181634683121
1234b25a1a361
1316bbc93b135
14a318c50bd7
1557626c02ad
hex312d1ade79

211210133113 has 8 divisors (see below), whose sum is σ = 241407062720. Its totient is φ = 181019216880.

The previous prime is 211210133059. The next prime is 211210133119. The reversal of 211210133113 is 311331012112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211210133113 is a prime.

It is a super-2 number, since 2×2112101331132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211210133119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1427823 + ... + 1568788.

It is an arithmetic number, because the mean of its divisors is an integer number (30175882840).

Almost surely, 2211210133113 is an apocalyptic number.

It is an amenable number.

211210133113 is a deficient number, since it is larger than the sum of its proper divisors (30196929607).

211210133113 is a wasteful number, since it uses less digits than its factorization.

211210133113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3006687.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 211210133113 its reverse (311331012112), we get a palindrome (522541145225).

The spelling of 211210133113 in words is "two hundred eleven billion, two hundred ten million, one hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 7 10069 70483 2996611 20976277 30172876159 211210133113