211212000000011 has 4 divisors (see below), whose sum is σ = 218025290322624. Its totient is φ = 204398709677400.

The previous prime is 211211999999981. The next prime is 211212000000031. The reversal of 211212000000011 is 110000000212112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211212000000011 is a prime.

It is a super-2 number, since 2×211212000000011² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211211999999929 and 211212000000001.

It is not an unprimeable number, because it can be changed into a prime (211212000000031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3406645161260 + ... + 3406645161321.

It is an arithmetic number, because the mean of its divisors is an integer number (54506322580656).

Almost surely, 2^{211212000000011} is an apocalyptic number.

211212000000011 is a deficient number, since it is larger than the sum of its proper divisors (6813290322613).

211212000000011 is an equidigital number, since it uses as much as digits as its factorization.

211212000000011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6813290322612.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 211212000000011 its reverse (110000000212112), we get a palindrome (321212000212123).

The spelling of 211212000000011 in words is "two hundred eleven trillion, two hundred twelve billion, eleven", and thus it is an aban number.