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21121314041 = 3141103316087
BaseRepresentation
bin10011101010111011…
…011010110011111001
32000111222110220221102
4103222323122303321
5321224024022131
613411503021145
71345256131022
oct235273326371
960458426842
1021121314041
118a59481943
12411559a7b5
131cb7aabb79
1410451b1c49
158394121cb
hex4eaedacf9

21121314041 has 16 divisors (see below), whose sum is σ = 22357429248. Its totient is φ = 19920902400.

The previous prime is 21121314001. The next prime is 21121314047. The reversal of 21121314041 is 14041312112.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21121314041 is a prime.

It is a super-2 number, since 2×211213140412 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (21121314047) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1304900 + ... + 1320986.

It is an arithmetic number, because the mean of its divisors is an integer number (1397339328).

Almost surely, 221121314041 is an apocalyptic number.

It is an amenable number.

21121314041 is a deficient number, since it is larger than the sum of its proper divisors (1236115207).

21121314041 is a wasteful number, since it uses less digits than its factorization.

21121314041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17192.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 21121314041 its reverse (14041312112), we get a palindrome (35162626153).

The spelling of 21121314041 in words is "twenty-one billion, one hundred twenty-one million, three hundred fourteen thousand, forty-one".

Divisors: 1 31 41 1033 1271 16087 32023 42353 498697 659567 1312943 16617871 20446577 515154001 681332711 21121314041