2112136441033 has 4 divisors (see below), whose sum is σ = 2124783964800. Its totient is φ = 2099488917268.

The previous prime is 2112136441027. The next prime is 2112136441057. The reversal of 2112136441033 is 3301446312112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2112136441033 - 2²¹ = 2112134343881 is a prime.

It is a super-2 number, since 2×2112136441033² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2112136440986 and 2112136441004.

It is not an unprimeable number, because it can be changed into a prime (2112136445033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6323761633 + ... + 6323761966.

It is an arithmetic number, because the mean of its divisors is an integer number (531195991200).

Almost surely, 2^{2112136441033} is an apocalyptic number.

It is an amenable number.

2112136441033 is a deficient number, since it is larger than the sum of its proper divisors (12647523767).

2112136441033 is a wasteful number, since it uses less digits than its factorization.

2112136441033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12647523766.

The product of its (nonzero) digits is 10368, while the sum is 31.

The spelling of 2112136441033 in words is "two trillion, one hundred twelve billion, one hundred thirty-six million, four hundred forty-one thousand, thirty-three".