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2112140403353 = 19131984279973
BaseRepresentation
bin11110101111000101011…
…000001110001010011001
321110220210200210120202102
4132233011120032022121
5234101130420401403
64254145351013145
7305411544130361
oct36570530161231
97426720716672
102112140403353
11744832215692
122a141b66a1b5
13124235327426
147432a0399a1
1539e1ce6db88
hex1ebc560e299

2112140403353 has 8 divisors (see below), whose sum is σ = 2224991313600. Its totient is φ = 1999458055728.

The previous prime is 2112140403283. The next prime is 2112140403377. The reversal of 2112140403353 is 3533040412112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2112140403353 - 222 = 2112136209049 is a prime.

It is a super-2 number, since 2×21121404033532 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2112140403383) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42114926 + ... + 42165047.

It is an arithmetic number, because the mean of its divisors is an integer number (278123914200).

Almost surely, 22112140403353 is an apocalyptic number.

It is an amenable number.

2112140403353 is a deficient number, since it is larger than the sum of its proper divisors (112850910247).

2112140403353 is a wasteful number, since it uses less digits than its factorization.

2112140403353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84281311.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 2112140403353 its reverse (3533040412112), we get a palindrome (5645180815465).

The spelling of 2112140403353 in words is "two trillion, one hundred twelve billion, one hundred forty million, four hundred three thousand, three hundred fifty-three".

Divisors: 1 19 1319 25061 84279973 1601319487 111165284387 2112140403353