211214100003 has 4 divisors (see below), whose sum is σ = 281618800008. Its totient is φ = 140809400000.

The previous prime is 211214099989. The next prime is 211214100007. The reversal of 211214100003 is 300001412112.

211214100003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 211214100003 - 2¹² = 211214095907 is a prime.

It is a super-2 number, since 2×211214100003² (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (211214100007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35202349998 + ... + 35202350003.

It is an arithmetic number, because the mean of its divisors is an integer number (70404700002).

Almost surely, 2^211214100003 is an apocalyptic number.

211214100003 is a deficient number, since it is larger than the sum of its proper divisors (70404700005).

211214100003 is an equidigital number, since it uses as much as digits as its factorization.

211214100003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70404700004.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 211214100003 its reverse (300001412112), we get a palindrome (511215512115).

The spelling of 211214100003 in words is "two hundred eleven billion, two hundred fourteen million, one hundred thousand, three".