Base | Representation |
---|---|
bin | 1100010010110110110… |
… | …0010111010011010011 |
3 | 202012012021200211202011 |
4 | 3010231230113103103 |
5 | 11430034310031003 |
6 | 241011053403351 |
7 | 21155141252053 |
oct | 3045554272323 |
9 | 665167624664 |
10 | 211220002003 |
11 | 8163a20382a |
12 | 34b29199557 |
13 | 16bc19b510a |
14 | a31a29d563 |
15 | 57634be46d |
hex | 312db174d3 |
211220002003 has 4 divisors (see below), whose sum is σ = 211222456768. Its totient is φ = 211217547240.
The previous prime is 211220002001. The next prime is 211220002057. The reversal of 211220002003 is 300200022112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 211220002003 - 21 = 211220002001 is a prime.
It is a super-2 number, since 2×2112200020032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (211220002001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1093443 + ... + 1272028.
It is an arithmetic number, because the mean of its divisors is an integer number (52805614192).
Almost surely, 2211220002003 is an apocalyptic number.
211220002003 is a deficient number, since it is larger than the sum of its proper divisors (2454765).
211220002003 is an equidigital number, since it uses as much as digits as its factorization.
211220002003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2454764.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 211220002003 its reverse (300200022112), we get a palindrome (511420024115).
The spelling of 211220002003 in words is "two hundred eleven billion, two hundred twenty million, two thousand, three".
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