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21122141403 = 3112812277811
BaseRepresentation
bin10011101010111110…
…100100110011011011
32000112001000221212110
4103222332210303123
5321224232011103
613411532443403
71345266145116
oct235276446333
960461027773
1021122141403
118a59997510
124115919563
131cb800b62c
14104534957d
15839527403
hex4eafa4cdb

21122141403 has 16 divisors (see below), whose sum is σ = 30832463232. Its totient is φ = 12755736000.

The previous prime is 21122141321. The next prime is 21122141459. The reversal of 21122141403 is 30414122112.

It is not a de Polignac number, because 21122141403 - 213 = 21122133211 is a prime.

It is a super-2 number, since 2×211221414032 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 21122141403.

It is not an unprimeable number, because it can be changed into a prime (21122141203) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1129633 + ... + 1148178.

It is an arithmetic number, because the mean of its divisors is an integer number (1927028952).

Almost surely, 221122141403 is an apocalyptic number.

21122141403 is a deficient number, since it is larger than the sum of its proper divisors (9710321829).

21122141403 is a wasteful number, since it uses less digits than its factorization.

21122141403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2278106.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 21122141403 its reverse (30414122112), we get a palindrome (51536263515).

The spelling of 21122141403 in words is "twenty-one billion, one hundred twenty-two million, one hundred forty-one thousand, four hundred three".

Divisors: 1 3 11 33 281 843 3091 9273 2277811 6833433 25055921 75167763 640064891 1920194673 7040713801 21122141403