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211223021431243 = 579908336423521
BaseRepresentation
bin110000000001101100110001…
…001010010010100111001011
31000200212201112112110022002211
4300001230301022102213023
5210141134221441244433
62025122303320205551
762330234243424403
oct6001546112224713
91020781475408084
10211223021431243
11613361a9030498
121b83452a6098b7
1390b2326355c63
143a2336a947803
1519645ded128cd
hexc01b312929cb

211223021431243 has 4 divisors (see below), whose sum is σ = 211223063653848. Its totient is φ = 211222979208640.

The previous prime is 211223021431193. The next prime is 211223021431249. The reversal of 211223021431243 is 342134120322112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211223021431243 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211223021431249) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12412678 + ... + 24010843.

It is an arithmetic number, because the mean of its divisors is an integer number (52805765913462).

Almost surely, 2211223021431243 is an apocalyptic number.

211223021431243 is a deficient number, since it is larger than the sum of its proper divisors (42222605).

211223021431243 is an equidigital number, since it uses as much as digits as its factorization.

211223021431243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42222604.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 211223021431243 its reverse (342134120322112), we get a palindrome (553357141753355).

The spelling of 211223021431243 in words is "two hundred eleven trillion, two hundred twenty-three billion, twenty-one million, four hundred thirty-one thousand, two hundred forty-three".

Divisors: 1 5799083 36423521 211223021431243