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2112250051 = 17124250003
BaseRepresentation
bin111110111100110…
…0110000011000011
312110012120102100101
41331321212003003
513311214000201
6545332503231
7103225554262
oct17571460303
95405512311
102112250051
119943457aa
124ab47ab17
132787b9902
141607585d9
15c5686d01
hex7de660c3

2112250051 has 4 divisors (see below), whose sum is σ = 2236500072. Its totient is φ = 1988000032.

The previous prime is 2112250039. The next prime is 2112250079. The reversal of 2112250051 is 1500522112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2112250051 - 211 = 2112248003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2112250031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62124985 + ... + 62125018.

It is an arithmetic number, because the mean of its divisors is an integer number (559125018).

Almost surely, 22112250051 is an apocalyptic number.

2112250051 is a deficient number, since it is larger than the sum of its proper divisors (124250021).

2112250051 is a wasteful number, since it uses less digits than its factorization.

2112250051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 124250020.

The product of its (nonzero) digits is 200, while the sum is 19.

The square root of 2112250051 is about 45959.2216100316. The cubic root of 2112250051 is about 1283.0643642910.

Adding to 2112250051 its reverse (1500522112), we get a palindrome (3612772163).

The spelling of 2112250051 in words is "two billion, one hundred twelve million, two hundred fifty thousand, fifty-one".

Divisors: 1 17 124250003 2112250051