Base | Representation |
---|---|
bin | 1001100110110000101010… |
… | …00011001010010110110001 |
3 | 2202210100011100102210121011 |
4 | 10303120111003022112301 |
5 | 10232034402042441423 |
6 | 112531435011030521 |
7 | 4310041455125602 |
oct | 463302503122661 |
9 | 82710140383534 |
10 | 21123002312113 |
11 | 6804240147629 |
12 | 245194289b441 |
13 | ba2b7677a680 |
14 | 530504655da9 |
15 | 2696cee51b0d |
hex | 1336150ca5b1 |
21123002312113 has 16 divisors (see below), whose sum is σ = 22957564605696. Its totient is φ = 19318525873920.
The previous prime is 21123002312081. The next prime is 21123002312147. The reversal of 21123002312113 is 31121320032112.
It is not a de Polignac number, because 21123002312113 - 25 = 21123002312081 is a prime.
It is a super-2 number, since 2×211230023121132 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (21123002312183) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1379256 + ... + 6644422.
It is an arithmetic number, because the mean of its divisors is an integer number (1434847787856).
Almost surely, 221123002312113 is an apocalyptic number.
It is an amenable number.
21123002312113 is a deficient number, since it is larger than the sum of its proper divisors (1834562293583).
21123002312113 is a wasteful number, since it uses less digits than its factorization.
21123002312113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5268024.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 21123002312113 its reverse (31121320032112), we get a palindrome (52244322344225).
The spelling of 21123002312113 in words is "twenty-one trillion, one hundred twenty-three billion, two million, three hundred twelve thousand, one hundred thirteen".
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