Base | Representation |
---|---|
bin | 1001100110110011010110… |
… | …00010101101101010001001 |
3 | 2202210110212220011201112112 |
4 | 10303121223002231222021 |
5 | 10232100330412111040 |
6 | 112532234105352105 |
7 | 4310122304100314 |
oct | 463315302555211 |
9 | 82713786151475 |
10 | 21124445035145 |
11 | 6804910566811 |
12 | 2452085a98635 |
13 | ba304663723a |
14 | 5306000c997b |
15 | 269766935365 |
hex | 13366b0ada89 |
21124445035145 has 4 divisors (see below), whose sum is σ = 25349334042180. Its totient is φ = 16899556028112.
The previous prime is 21124445035097. The next prime is 21124445035157. The reversal of 21124445035145 is 54153054442112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2815425593929 + 18309019441216 = 1677923^2 + 4278904^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21124445035145 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2112444503510 + ... + 2112444503519.
It is an arithmetic number, because the mean of its divisors is an integer number (6337333510545).
Almost surely, 221124445035145 is an apocalyptic number.
It is an amenable number.
21124445035145 is a deficient number, since it is larger than the sum of its proper divisors (4224889007035).
21124445035145 is an equidigital number, since it uses as much as digits as its factorization.
21124445035145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4224889007034.
The product of its (nonzero) digits is 384000, while the sum is 41.
Adding to 21124445035145 its reverse (54153054442112), we get a palindrome (75277499477257).
The spelling of 21124445035145 in words is "twenty-one trillion, one hundred twenty-four billion, four hundred forty-five million, thirty-five thousand, one hundred forty-five".
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