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211253130035 = 5371141908811
BaseRepresentation
bin1100010010111110101…
…0101111001100110011
3202012021121000220212022
43010233222233030303
511430121300130120
6241014235422055
721156022656203
oct3045752571463
9665247026768
10211253130035
1181656980372
1234b382b492b
1316bc8813abc
14a320844403
155766365025
hex312faaf333

211253130035 has 8 divisors (see below), whose sum is σ = 260355209136. Its totient is φ = 164434868640.

The previous prime is 211253129963. The next prime is 211253130037. The reversal of 211253130035 is 530031352112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 211253130035 - 210 = 211253129011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211253129986 and 211253130013.

It is not an unprimeable number, because it can be changed into a prime (211253130037) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 570954221 + ... + 570954590.

It is an arithmetic number, because the mean of its divisors is an integer number (32544401142).

Almost surely, 2211253130035 is an apocalyptic number.

211253130035 is a deficient number, since it is larger than the sum of its proper divisors (49102079101).

211253130035 is a wasteful number, since it uses less digits than its factorization.

211253130035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1141908853.

The product of its (nonzero) digits is 2700, while the sum is 26.

Adding to 211253130035 its reverse (530031352112), we get a palindrome (741284482147).

The spelling of 211253130035 in words is "two hundred eleven billion, two hundred fifty-three million, one hundred thirty thousand, thirty-five".

Divisors: 1 5 37 185 1141908811 5709544055 42250626007 211253130035