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211300233113 = 1911106283943
BaseRepresentation
bin1100010011001001111…
…0011010111110011001
3202012101212200000010202
43010302132122332121
511430220324424423
6241023041151545
721160134230024
oct3046236327631
9665355600122
10211300233113
1181680522632
1234b5002b5b5
1316c054c6748
14a326bc61bb
15576a56b728
hex313279af99

211300233113 has 4 divisors (see below), whose sum is σ = 212406517248. Its totient is φ = 210193948980.

The previous prime is 211300233029. The next prime is 211300233167. The reversal of 211300233113 is 311332003112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211300233113 - 216 = 211300167577 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211300233413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 553141781 + ... + 553142162.

It is an arithmetic number, because the mean of its divisors is an integer number (53101629312).

Almost surely, 2211300233113 is an apocalyptic number.

It is an amenable number.

211300233113 is a deficient number, since it is larger than the sum of its proper divisors (1106284135).

211300233113 is a wasteful number, since it uses less digits than its factorization.

211300233113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1106284134.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 211300233113 its reverse (311332003112), we get a palindrome (522632236225).

The spelling of 211300233113 in words is "two hundred eleven billion, three hundred million, two hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 191 1106283943 211300233113