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21130045441305 = 3510911291172957
BaseRepresentation
bin1001100110111101110001…
…10110100100010100011001
32202211000100012022211111220
410303132320312210110121
510232143313113110210
6112535001525442253
74310411136545133
oct463367066442431
982730305284456
1021130045441305
116807224879859
122453189570389
13ba37299a4538
145309b1bdc053
15269993439c70
hex1337b8da4519

21130045441305 has 16 divisors (see below), whose sum is σ = 33839060883264. Its totient is φ = 11259028176320.

The previous prime is 21130045441259. The next prime is 21130045441363. The reversal of 21130045441305 is 50314454003112.

It is not a de Polignac number, because 21130045441305 - 28 = 21130045441049 is a prime.

It is a super-2 number, since 2×211300454413052 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 645570114 + ... + 645602843.

It is an arithmetic number, because the mean of its divisors is an integer number (2114941305204).

Almost surely, 221130045441305 is an apocalyptic number.

It is an amenable number.

21130045441305 is a deficient number, since it is larger than the sum of its proper divisors (12709015441959).

21130045441305 is a wasteful number, since it uses less digits than its factorization.

21130045441305 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1291174056.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 21130045441305 its reverse (50314454003112), we get a palindrome (71444499444417).

The spelling of 21130045441305 in words is "twenty-one trillion, one hundred thirty billion, forty-five million, four hundred forty-one thousand, three hundred five".

Divisors: 1 3 5 15 1091 3273 5455 16365 1291172957 3873518871 6455864785 19367594355 1408669696087 4226009088261 7043348480435 21130045441305