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2113010220131 = 15971323112223
BaseRepresentation
bin11110101111111001001…
…110010011110001100011
321111000001022111212001122
4132233321032103301203
5234104421104021011
64254411542122455
7305442235345346
oct36577116236143
97430038455048
102113010220131
11745139201928
122a1622a2042b
131243435b3605
14743ad77a45d
1539e6e4d73db
hex1ebf9393c63

2113010220131 has 4 divisors (see below), whose sum is σ = 2114333333952. Its totient is φ = 2111687106312.

The previous prime is 2113010220121. The next prime is 2113010220137. The reversal of 2113010220131 is 1310220103112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2113010220131 is a prime.

It is a super-2 number, since 2×21130102201312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2113010220137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 661554515 + ... + 661557708.

It is an arithmetic number, because the mean of its divisors is an integer number (528583333488).

Almost surely, 22113010220131 is an apocalyptic number.

2113010220131 is a deficient number, since it is larger than the sum of its proper divisors (1323113821).

2113010220131 is a wasteful number, since it uses less digits than its factorization.

2113010220131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1323113820.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 2113010220131 its reverse (1310220103112), we get a palindrome (3423230323243).

The spelling of 2113010220131 in words is "two trillion, one hundred thirteen billion, ten million, two hundred twenty thousand, one hundred thirty-one".

Divisors: 1 1597 1323112223 2113010220131