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2113050115 = 51138419093
BaseRepresentation
bin111110111110010…
…1001011000000011
312110021002001211101
41331330221120003
513311420100430
6545401555231
7103235425651
oct17574513003
95407061741
102113050115
11994841910
124ab7a5b17
13278a09b17
141608c5dd1
15c5793dca
hex7df29603

2113050115 has 8 divisors (see below), whose sum is σ = 2766174768. Its totient is φ = 1536763680.

The previous prime is 2113050091. The next prime is 2113050127. The reversal of 2113050115 is 5110503112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2113050115 - 213 = 2113041923 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2113050092 and 2113050101.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19209492 + ... + 19209601.

It is an arithmetic number, because the mean of its divisors is an integer number (345771846).

Almost surely, 22113050115 is an apocalyptic number.

2113050115 is a deficient number, since it is larger than the sum of its proper divisors (653124653).

2113050115 is a wasteful number, since it uses less digits than its factorization.

2113050115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38419109.

The product of its (nonzero) digits is 150, while the sum is 19.

The square root of 2113050115 is about 45967.9248498342. The cubic root of 2113050115 is about 1283.2263406988.

Adding to 2113050115 its reverse (5110503112), we get a palindrome (7223553227).

The spelling of 2113050115 in words is "two billion, one hundred thirteen million, fifty thousand, one hundred fifteen".

Divisors: 1 5 11 55 38419093 192095465 422610023 2113050115