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21131001313 = 49367428039
BaseRepresentation
bin10011101011100000…
…010111110111100001
32000112122201002101021
4103223200113313201
5321234014020223
613412450405441
71345434355552
oct235340276741
960478632337
1021131001313
118a63999054
124118890881
131cb9ac1296
1410465b4329
1583a1c765d
hex4eb817de1

21131001313 has 4 divisors (see below), whose sum is σ = 21131478720. Its totient is φ = 21130523908.

The previous prime is 21131001289. The next prime is 21131001319. The reversal of 21131001313 is 31310013112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21131001313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21131001319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 164653 + ... + 263386.

It is an arithmetic number, because the mean of its divisors is an integer number (5282869680).

Almost surely, 221131001313 is an apocalyptic number.

It is an amenable number.

21131001313 is a deficient number, since it is larger than the sum of its proper divisors (477407).

21131001313 is an equidigital number, since it uses as much as digits as its factorization.

21131001313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 477406.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 21131001313 its reverse (31310013112), we get a palindrome (52441014425).

The spelling of 21131001313 in words is "twenty-one billion, one hundred thirty-one million, one thousand, three hundred thirteen".

Divisors: 1 49367 428039 21131001313