21131010110113 has 4 divisors (see below), whose sum is σ = 21812655597568. Its totient is φ = 20449364622660.

The previous prime is 21131010110101. The next prime is 21131010110117. The reversal of 21131010110113 is 31101101013112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21131010110113 - 2²⁹ = 21130473239201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21131010110117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 340822743681 + ... + 340822743742.

It is an arithmetic number, because the mean of its divisors is an integer number (5453163899392).

Almost surely, 2^{21131010110113} is an apocalyptic number.

It is an amenable number.

21131010110113 is a deficient number, since it is larger than the sum of its proper divisors (681645487455).

21131010110113 is an equidigital number, since it uses as much as digits as its factorization.

21131010110113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 681645487454.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 21131010110113 its reverse (31101101013112), we get a palindrome (52232111123225).

The spelling of 21131010110113 in words is "twenty-one trillion, one hundred thirty-one billion, ten million, one hundred ten thousand, one hundred thirteen".