Search a number
-
+
211312434212203 = 239187497139661
BaseRepresentation
bin110000000011000000000010…
…100100111110110101101011
31000201012021022212101012010211
4300003000002210332311223
5210144120331124242303
62025231331522321551
762336551052503162
oct6003000244766553
91021167285335124
10211312434212203
1161370111233195
121b8499227b92b7
1390ba8a5605c3c
143a2780d8683d9
151966ac484866d
hexc0300293ed6b

211312434212203 has 4 divisors (see below), whose sum is σ = 220499931351888. Its totient is φ = 202124937072520.

The previous prime is 211312434212189. The next prime is 211312434212207. The reversal of 211312434212203 is 302212434213112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 211312434212203 - 221 = 211312432115051 is a prime.

It is a super-2 number, since 2×2113124342122032 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211312434212207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4593748569808 + ... + 4593748569853.

It is an arithmetic number, because the mean of its divisors is an integer number (55124982837972).

Almost surely, 2211312434212203 is an apocalyptic number.

211312434212203 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

211312434212203 is a deficient number, since it is larger than the sum of its proper divisors (9187497139685).

211312434212203 is an equidigital number, since it uses as much as digits as its factorization.

211312434212203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9187497139684.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 211312434212203 its reverse (302212434213112), we get a palindrome (513524868425315).

Subtracting 211312434212203 from its reverse (302212434213112), we obtain a palindrome (90900000000909).

The spelling of 211312434212203 in words is "two hundred eleven trillion, three hundred twelve billion, four hundred thirty-four million, two hundred twelve thousand, two hundred three".

Divisors: 1 23 9187497139661 211312434212203