Base | Representation |
---|---|
bin | 110000000011000010101110… |
… | …000111110011111001001001 |
3 | 1000201012112202102220110202221 |
4 | 300003002232013303321021 |
5 | 210144142224413340340 |
6 | 2025232525252454041 |
7 | 62340012300416236 |
oct | 6003025607637111 |
9 | 1021175672813687 |
10 | 211315312246345 |
11 | 613713588698aa |
12 | 1b84a3a661a321 |
13 | 90bac43955818 |
14 | 3a27a03ba278d |
15 | 1966be234944a |
hex | c030ae1f3e49 |
211315312246345 has 16 divisors (see below), whose sum is σ = 254945407919040. Its totient is φ = 168142356000064.
The previous prime is 211315312246237. The next prime is 211315312246361. The reversal of 211315312246345 is 543642213513112.
It is a cyclic number.
It is not a de Polignac number, because 211315312246345 - 221 = 211315310149193 is a prime.
It is a super-2 number, since 2×2113153122463452 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 90198142 + ... + 92511271.
It is an arithmetic number, because the mean of its divisors is an integer number (15934087994940).
Almost surely, 2211315312246345 is an apocalyptic number.
It is an amenable number.
211315312246345 is a deficient number, since it is larger than the sum of its proper divisors (43630095672695).
211315312246345 is a wasteful number, since it uses less digits than its factorization.
211315312246345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 182710664.
The product of its digits is 518400, while the sum is 43.
Adding to 211315312246345 its reverse (543642213513112), we get a palindrome (754957525759457).
The spelling of 211315312246345 in words is "two hundred eleven trillion, three hundred fifteen billion, three hundred twelve million, two hundred forty-six thousand, three hundred forty-five".
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