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2113202554561 = 7417363075103
BaseRepresentation
bin11110110000000100101…
…100000000011011000001
321111000112201102110022001
4132300010230000123001
5234110314323221221
64254443012344001
7305450062225210
oct36600454003301
97430481373261
102113202554561
117452278295aa
122a1677315001
131243743b5777
14743cb125077
1539e8132a391
hex1ec04b006c1

2113202554561 has 8 divisors (see below), whose sum is σ = 2473993234944. Its totient is φ = 1767138024480.

The previous prime is 2113202554543. The next prime is 2113202554583. The reversal of 2113202554561 is 1654552023112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2113202554561 - 219 = 2113202030273 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2113202554561.

It is not an unprimeable number, because it can be changed into a prime (2113202554961) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3681537265 + ... + 3681537838.

It is an arithmetic number, because the mean of its divisors is an integer number (309249154368).

Almost surely, 22113202554561 is an apocalyptic number.

It is an amenable number.

2113202554561 is a deficient number, since it is larger than the sum of its proper divisors (360790680383).

2113202554561 is an equidigital number, since it uses as much as digits as its factorization.

2113202554561 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7363075151.

The product of its (nonzero) digits is 72000, while the sum is 37.

Adding to 2113202554561 its reverse (1654552023112), we get a palindrome (3767754577673).

The spelling of 2113202554561 in words is "two trillion, one hundred thirteen billion, two hundred two million, five hundred fifty-four thousand, five hundred sixty-one".

Divisors: 1 7 41 287 7363075103 51541525721 301886079223 2113202554561