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2113203115 = 56759910531
BaseRepresentation
bin111110111110100…
…1110101110101011
312110021100211201001
41331331032232223
513311434444430
6545405135431
7103236634012
oct17575165653
95407324631
102113203115
11994936861
124ab85a577
13278a6165a
14160925a79
15c57c43ca
hex7df4ebab

2113203115 has 16 divisors (see below), whose sum is σ = 2578233600. Its totient is φ = 1662392160.

The previous prime is 2113203107. The next prime is 2113203149. The reversal of 2113203115 is 5113023112.

It is not a de Polignac number, because 2113203115 - 23 = 2113203107 is a prime.

It is a super-3 number, since 3×21132031153 (a number of 29 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2113203092 and 2113203101.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 195400 + ... + 205930.

It is an arithmetic number, because the mean of its divisors is an integer number (161139600).

Almost surely, 22113203115 is an apocalyptic number.

2113203115 is a deficient number, since it is larger than the sum of its proper divisors (465030485).

2113203115 is a wasteful number, since it uses less digits than its factorization.

2113203115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11202.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 2113203115 is about 45969.5890236143. The cubic root of 2113203115 is about 1283.2573115515.

Adding to 2113203115 its reverse (5113023112), we get a palindrome (7226226227).

The spelling of 2113203115 in words is "two billion, one hundred thirteen million, two hundred three thousand, one hundred fifteen".

Divisors: 1 5 67 335 599 2995 10531 40133 52655 200665 705577 3527885 6308069 31540345 422640623 2113203115