Base | Representation |
---|---|
bin | 110000000011001000000111… |
… | …101101110011000110110001 |
3 | 1000201020002201112001100122201 |
4 | 300003020013231303012301 |
5 | 210144241113222002423 |
6 | 2025235324454103201 |
7 | 62340306053425330 |
oct | 6003100755630661 |
9 | 1021202645040581 |
10 | 211321110344113 |
11 | 61373863728540 |
12 | 1b84b54434ab01 |
13 | 90bb658c4c4c3 |
14 | 3a27dd3c55d17 |
15 | 1966e3139e2ad |
hex | c03207b731b1 |
211321110344113 has 16 divisors (see below), whose sum is σ = 263535744890880. Its totient is φ = 164621759979600.
The previous prime is 211321110344111. The next prime is 211321110344143. The reversal of 211321110344113 is 311443011123112.
It is not a de Polignac number, because 211321110344113 - 21 = 211321110344111 is a prime.
It is a super-2 number, since 2×2113211103441132 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (211321110344111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 366712633 + ... + 367288438.
It is an arithmetic number, because the mean of its divisors is an integer number (16470984055680).
Almost surely, 2211321110344113 is an apocalyptic number.
It is an amenable number.
211321110344113 is a deficient number, since it is larger than the sum of its proper divisors (52214634546767).
211321110344113 is a wasteful number, since it uses less digits than its factorization.
211321110344113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 734004828.
The product of its (nonzero) digits is 1728, while the sum is 28.
Adding to 211321110344113 its reverse (311443011123112), we get a palindrome (522764121467225).
The spelling of 211321110344113 in words is "two hundred eleven trillion, three hundred twenty-one billion, one hundred ten million, three hundred forty-four thousand, one hundred thirteen".
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