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211323000001 = 1791180575419
BaseRepresentation
bin1100010011001111010…
…1010001010011000001
3202012110110111200102211
43010303311101103001
511430242142000001
6241025213142121
721160531601551
oct3046365212301
9665413450384
10211323000001
1181692362743
1234b5778a941
1316c0a138389
14a329c31161
15576c567351
hex3133d514c1

211323000001 has 4 divisors (see below), whose sum is σ = 212503575600. Its totient is φ = 210142424404.

The previous prime is 211322999981. The next prime is 211323000011. The reversal of 211323000001 is 100000323112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211323000001 - 25 = 211322999969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211323000011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 590287531 + ... + 590287888.

It is an arithmetic number, because the mean of its divisors is an integer number (53125893900).

Almost surely, 2211323000001 is an apocalyptic number.

It is an amenable number.

211323000001 is a deficient number, since it is larger than the sum of its proper divisors (1180575599).

211323000001 is a wasteful number, since it uses less digits than its factorization.

211323000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1180575598.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 211323000001 its reverse (100000323112), we get a palindrome (311323323113).

The spelling of 211323000001 in words is "two hundred eleven billion, three hundred twenty-three million, one", and thus it is an aban number.

Divisors: 1 179 1180575419 211323000001