Base | Representation |
---|---|
bin | 1100010011001111010… |
… | …1010001010011000001 |
3 | 202012110110111200102211 |
4 | 3010303311101103001 |
5 | 11430242142000001 |
6 | 241025213142121 |
7 | 21160531601551 |
oct | 3046365212301 |
9 | 665413450384 |
10 | 211323000001 |
11 | 81692362743 |
12 | 34b5778a941 |
13 | 16c0a138389 |
14 | a329c31161 |
15 | 576c567351 |
hex | 3133d514c1 |
211323000001 has 4 divisors (see below), whose sum is σ = 212503575600. Its totient is φ = 210142424404.
The previous prime is 211322999981. The next prime is 211323000011. The reversal of 211323000001 is 100000323112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 211323000001 - 25 = 211322999969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (211323000011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 590287531 + ... + 590287888.
It is an arithmetic number, because the mean of its divisors is an integer number (53125893900).
Almost surely, 2211323000001 is an apocalyptic number.
It is an amenable number.
211323000001 is a deficient number, since it is larger than the sum of its proper divisors (1180575599).
211323000001 is a wasteful number, since it uses less digits than its factorization.
211323000001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1180575598.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 211323000001 its reverse (100000323112), we get a palindrome (311323323113).
The spelling of 211323000001 in words is "two hundred eleven billion, three hundred twenty-three million, one", and thus it is an aban number.
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