2113304333433 has 4 divisors (see below), whose sum is σ = 2817739111248. Its totient is φ = 1408869555620.

The previous prime is 2113304333429. The next prime is 2113304333449. The reversal of 2113304333433 is 3343334033112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2113304333433 - 2² = 2113304333429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2113304333394 and 2113304333403.

It is not an unprimeable number, because it can be changed into a prime (2113304333533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352217388903 + ... + 352217388908.

It is an arithmetic number, because the mean of its divisors is an integer number (704434777812).

Almost surely, 2^{2113304333433} is an apocalyptic number.

It is an amenable number.

2113304333433 is a deficient number, since it is larger than the sum of its proper divisors (704434777815).

2113304333433 is an equidigital number, since it uses as much as digits as its factorization.

2113304333433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 704434777814.

The product of its (nonzero) digits is 69984, while the sum is 33.

Adding to 2113304333433 its reverse (3343334033112), we get a palindrome (5456638366545).

The spelling of 2113304333433 in words is "two trillion, one hundred thirteen billion, three hundred four million, three hundred thirty-three thousand, four hundred thirty-three".