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211331133113 = 905923328307
BaseRepresentation
bin1100010011010001010…
…0010010111010111001
3202012111000210212222012
43010310110102322321
511430301232224423
6241030103335305
721160660664342
oct3046424227271
9665430725865
10211331133113
1181696a08221
1234b5a451535
1316c0ba25279
14a32ad4b0c9
15576d122078
hex3134512eb9

211331133113 has 4 divisors (see below), whose sum is σ = 211354470480. Its totient is φ = 211307795748.

The previous prime is 211331133077. The next prime is 211331133119. The reversal of 211331133113 is 311331133112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211331133113 - 218 = 211330870969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211331133119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11655095 + ... + 11673212.

It is an arithmetic number, because the mean of its divisors is an integer number (52838617620).

Almost surely, 2211331133113 is an apocalyptic number.

It is an amenable number.

211331133113 is a deficient number, since it is larger than the sum of its proper divisors (23337367).

211331133113 is an equidigital number, since it uses as much as digits as its factorization.

211331133113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23337366.

The product of its digits is 486, while the sum is 23.

Adding to 211331133113 its reverse (311331133112), we get a palindrome (522662266225).

Subtracting 211331133113 from its reverse (311331133112), we obtain a palindrome (99999999999).

The spelling of 211331133113 in words is "two hundred eleven billion, three hundred thirty-one million, one hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 9059 23328307 211331133113