21133142113 has 4 divisors (see below), whose sum is σ = 21136307248. Its totient is φ = 21129976980.

The previous prime is 21133142083. The next prime is 21133142137. The reversal of 21133142113 is 31124133112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-21133142113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21133142413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1572531 + ... + 1585912.

It is an arithmetic number, because the mean of its divisors is an integer number (5284076812).

Almost surely, 2^21133142113 is an apocalyptic number.

It is an amenable number.

21133142113 is a deficient number, since it is larger than the sum of its proper divisors (3165135).

21133142113 is an equidigital number, since it uses as much as digits as its factorization.

21133142113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3165134.

The product of its digits is 432, while the sum is 22.

Adding to 21133142113 its reverse (31124133112), we get a palindrome (52257275225).

Subtracting 21133142113 from its reverse (31124133112), we obtain a palindrome (9990990999).

The spelling of 21133142113 in words is "twenty-one billion, one hundred thirty-three million, one hundred forty-two thousand, one hundred thirteen".