2113324440041 has 4 divisors (see below), whose sum is σ = 2140075382400. Its totient is φ = 2086573497684.

The previous prime is 2113324439987. The next prime is 2113324440077. The reversal of 2113324440041 is 1400444233112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2113324440041 - 2⁶ = 2113324439977 is a prime.

It is a super-2 number, since 2×2113324440041² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2113324439986 and 2113324440013.

It is not an unprimeable number, because it can be changed into a prime (2113324470041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13375471061 + ... + 13375471218.

It is an arithmetic number, because the mean of its divisors is an integer number (535018845600).

Almost surely, 2^{2113324440041} is an apocalyptic number.

It is an amenable number.

2113324440041 is a deficient number, since it is larger than the sum of its proper divisors (26750942359).

2113324440041 is an equidigital number, since it uses as much as digits as its factorization.

2113324440041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26750942358.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 2113324440041 its reverse (1400444233112), we get a palindrome (3513768673153).

The spelling of 2113324440041 in words is "two trillion, one hundred thirteen billion, three hundred twenty-four million, four hundred forty thousand, forty-one".