Base | Representation |
---|---|
bin | 11110110000001100011… |
… | …011011100100110010011 |
3 | 21111000212202210212121211 |
4 | 132300030123130212103 |
5 | 234111101100300001 |
6 | 4254503532200551 |
7 | 305453230163356 |
oct | 36601433344623 |
9 | 7430782725554 |
10 | 2113332431251 |
11 | 745294076908 |
12 | 2a16b2909157 |
13 | 12439528a092 |
14 | 7440049229d |
15 | 39e8c932351 |
hex | 1ec0c6dc993 |
2113332431251 has 4 divisors (see below), whose sum is σ = 2114077352112. Its totient is φ = 2112587510392.
The previous prime is 2113332431237. The next prime is 2113332431263. The reversal of 2113332431251 is 1521342333112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2113332431251 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2113332431201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 372456175 + ... + 372461848.
It is an arithmetic number, because the mean of its divisors is an integer number (528519338028).
Almost surely, 22113332431251 is an apocalyptic number.
2113332431251 is a deficient number, since it is larger than the sum of its proper divisors (744920861).
2113332431251 is an equidigital number, since it uses as much as digits as its factorization.
2113332431251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 744920860.
The product of its digits is 12960, while the sum is 31.
Adding to 2113332431251 its reverse (1521342333112), we get a palindrome (3634674764363).
The spelling of 2113332431251 in words is "two trillion, one hundred thirteen billion, three hundred thirty-two million, four hundred thirty-one thousand, two hundred fifty-one".
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