Base | Representation |
---|---|
bin | 11110110000010111000… |
… | …111000100001010001001 |
3 | 21111001100021000111120112 |
4 | 132300113013010022021 |
5 | 234111432434401031 |
6 | 4254533413204105 |
7 | 305460534335105 |
oct | 36602707041211 |
9 | 7431307014515 |
10 | 2113511637641 |
11 | 745376247268 |
12 | 2a1742930635 |
13 | 1243c3443971 |
14 | 7441a1c0905 |
15 | 39e9d53062b |
hex | 1ec171c4289 |
2113511637641 has 4 divisors (see below), whose sum is σ = 2113521591300. Its totient is φ = 2113501683984.
The previous prime is 2113511637599. The next prime is 2113511637649. The reversal of 2113511637641 is 1467361153112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 551521596025 + 1561990041616 = 742645^2 + 1249796^2 .
It is a cyclic number.
It is not a de Polignac number, because 2113511637641 - 226 = 2113444528777 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2113511637649) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4651226 + ... + 5085363.
It is an arithmetic number, because the mean of its divisors is an integer number (528380397825).
Almost surely, 22113511637641 is an apocalyptic number.
It is an amenable number.
2113511637641 is a deficient number, since it is larger than the sum of its proper divisors (9953659).
2113511637641 is an equidigital number, since it uses as much as digits as its factorization.
2113511637641 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9953658.
The product of its digits is 90720, while the sum is 41.
The spelling of 2113511637641 in words is "two trillion, one hundred thirteen billion, five hundred eleven million, six hundred thirty-seven thousand, six hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •