Base | Representation |
---|---|
bin | 111111000000001… |
… | …1011001001110001 |
3 | 12110022221101021211 |
4 | 1332000123021301 |
5 | 13312143243213 |
6 | 545435120121 |
7 | 103250022121 |
oct | 17600331161 |
9 | 5408841254 |
10 | 2114040433 |
11 | 99535895a |
12 | 4abba3041 |
13 | 278c957cb |
14 | 160aa2c81 |
15 | c58dc53d |
hex | 7e01b271 |
2114040433 has 4 divisors (see below), whose sum is σ = 2163204208. Its totient is φ = 2064876660.
The previous prime is 2114040421. The next prime is 2114040437. The reversal of 2114040433 is 3340404112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2114040433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2114040437) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24581823 + ... + 24581908.
It is an arithmetic number, because the mean of its divisors is an integer number (540801052).
Almost surely, 22114040433 is an apocalyptic number.
It is an amenable number.
2114040433 is a deficient number, since it is larger than the sum of its proper divisors (49163775).
2114040433 is an equidigital number, since it uses as much as digits as its factorization.
2114040433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49163774.
The product of its (nonzero) digits is 1152, while the sum is 22.
The square root of 2114040433 is about 45978.6954251640. The cubic root of 2114040433 is about 1283.4267782335.
Adding to 2114040433 its reverse (3340404112), we get a palindrome (5454444545).
The spelling of 2114040433 in words is "two billion, one hundred fourteen million, forty thousand, four hundred thirty-three".
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