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2114043403 = 3154367021
BaseRepresentation
bin111111000000001…
…1011111000001011
312110022221112100211
41332000123320023
513312143342103
6545435141551
7103250033563
oct17600337013
95408845324
102114043403
1199536010a
124abba48b7
13278c96c74
14160aa3da3
15c58dd36d
hex7e01be0b

2114043403 has 4 divisors (see below), whose sum is σ = 2114141968. Its totient is φ = 2113944840.

The previous prime is 2114043361. The next prime is 2114043431. The reversal of 2114043403 is 3043404112.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 2114043403 - 29 = 2114042891 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2114043473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1968 + ... + 65053.

It is an arithmetic number, because the mean of its divisors is an integer number (528535492).

Almost surely, 22114043403 is an apocalyptic number.

2114043403 is a deficient number, since it is larger than the sum of its proper divisors (98565).

2114043403 is an equidigital number, since it uses as much as digits as its factorization.

2114043403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 98564.

The product of its (nonzero) digits is 1152, while the sum is 22.

The square root of 2114043403 is about 45978.7277227198. The cubic root of 2114043403 is about 1283.4273792588.

Adding to 2114043403 its reverse (3043404112), we get a palindrome (5157447515).

The spelling of 2114043403 in words is "two billion, one hundred fourteen million, forty-three thousand, four hundred three".

Divisors: 1 31543 67021 2114043403