Search a number
-
+
21141154451 = 25703822517
BaseRepresentation
bin10011101100000111…
…000110101010010011
32000120100210220212102
4103230013012222103
5321244113420301
613413452151015
71345616563544
oct235407065223
960510726772
1021141154451
118a696a327a
12412016846b
131cbbc37761
141047a984cb
1583b030b6b
hex4ec1c6a93

21141154451 has 4 divisors (see below), whose sum is σ = 21142002672. Its totient is φ = 21140306232.

The previous prime is 21141154427. The next prime is 21141154487. The reversal of 21141154451 is 15445114112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21141154451 is a prime.

It is a super-2 number, since 2×211411544512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21141114451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385556 + ... + 436961.

It is an arithmetic number, because the mean of its divisors is an integer number (5285500668).

Almost surely, 221141154451 is an apocalyptic number.

21141154451 is a deficient number, since it is larger than the sum of its proper divisors (848221).

21141154451 is an equidigital number, since it uses as much as digits as its factorization.

21141154451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 848220.

The product of its digits is 3200, while the sum is 29.

Adding to 21141154451 its reverse (15445114112), we get a palindrome (36586268563).

The spelling of 21141154451 in words is "twenty-one billion, one hundred forty-one million, one hundred fifty-four thousand, four hundred fifty-one".

Divisors: 1 25703 822517 21141154451