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21141311241 = 37047103747
BaseRepresentation
bin10011101100000111…
…101100111100001001
32000120101002212221110
4103230013230330021
5321244133424431
613413455400533
71345621115631
oct235407547411
960511085843
1021141311241
118a697a0056
124120223149
131cbbc90c2b
141047ad96c1
1583b062346
hex4ec1ecf09

21141311241 has 4 divisors (see below), whose sum is σ = 28188414992. Its totient is φ = 14094207492.

The previous prime is 21141311221. The next prime is 21141311263. The reversal of 21141311241 is 14211314112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 21141311241 - 223 = 21132922633 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (21141311221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3523551871 + ... + 3523551876.

It is an arithmetic number, because the mean of its divisors is an integer number (7047103748).

Almost surely, 221141311241 is an apocalyptic number.

It is an amenable number.

21141311241 is a deficient number, since it is larger than the sum of its proper divisors (7047103751).

21141311241 is an equidigital number, since it uses as much as digits as its factorization.

21141311241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7047103750.

The product of its digits is 192, while the sum is 21.

Adding to 21141311241 its reverse (14211314112), we get a palindrome (35352625353).

The spelling of 21141311241 in words is "twenty-one billion, one hundred forty-one million, three hundred eleven thousand, two hundred forty-one".

Divisors: 1 3 7047103747 21141311241