Base | Representation |
---|---|
bin | 1001100111010100010000… |
… | …01100111011111010001011 |
3 | 2202212011111021200101222202 |
4 | 10303222020030323322023 |
5 | 10232343022203422103 |
6 | 112544315251310415 |
7 | 4311316203626210 |
oct | 463521014737213 |
9 | 82764437611882 |
10 | 21142114123403 |
11 | 6811358281299 |
12 | 24555972ab40b |
13 | ba4901135a50 |
14 | 5313d89b7b07 |
15 | 269e4cc25988 |
hex | 133a8833be8b |
21142114123403 has 16 divisors (see below), whose sum is σ = 26655723627456. Its totient is φ = 16319830786560.
The previous prime is 21142114123271. The next prime is 21142114123409. The reversal of 21142114123403 is 30432141124112.
It is not a de Polignac number, because 21142114123403 - 210 = 21142114122379 is a prime.
It is a super-2 number, since 2×211421141234032 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (21142114123409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2833300226 + ... + 2833307687.
It is an arithmetic number, because the mean of its divisors is an integer number (1665982726716).
Almost surely, 221142114123403 is an apocalyptic number.
21142114123403 is a deficient number, since it is larger than the sum of its proper divisors (5513609504053).
21142114123403 is a wasteful number, since it uses less digits than its factorization.
21142114123403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5666607974.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 21142114123403 its reverse (30432141124112), we get a palindrome (51574255247515).
The spelling of 21142114123403 in words is "twenty-one trillion, one hundred forty-two billion, one hundred fourteen million, one hundred twenty-three thousand, four hundred three".
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