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211431400113 = 3196755363027
BaseRepresentation
bin1100010011101001001…
…0110010001010110001
3202012202000110222102210
43010322102302022301
511431002414300423
6241044044402333
721163316151063
oct3047222621261
9665660428383
10211431400113
118173857130a
1234b87b463a9
1316c2673045b
14a33a3ab733
155776d2ab93
hex313a4b22b1

211431400113 has 16 divisors (see below), whose sum is σ = 301174872320. Its totient is φ = 131542549776.

The previous prime is 211431400091. The next prime is 211431400121. The reversal of 211431400113 is 311004134112.

It is not a de Polignac number, because 211431400113 - 212 = 211431396017 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 211431400113.

It is not an unprimeable number, because it can be changed into a prime (211431400183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27677695 + ... + 27685332.

It is an arithmetic number, because the mean of its divisors is an integer number (18823429520).

Almost surely, 2211431400113 is an apocalyptic number.

It is an amenable number.

211431400113 is a deficient number, since it is larger than the sum of its proper divisors (89743472207).

211431400113 is a wasteful number, since it uses less digits than its factorization.

211431400113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55363116.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 211431400113 its reverse (311004134112), we get a palindrome (522435534225).

The spelling of 211431400113 in words is "two hundred eleven billion, four hundred thirty-one million, four hundred thousand, one hundred thirteen".

Divisors: 1 3 19 57 67 201 1273 3819 55363027 166089081 1051897513 3155692539 3709322809 11127968427 70477133371 211431400113