2114350534113 has 4 divisors (see below), whose sum is σ = 2819134045488. Its totient is φ = 1409567022740.

The previous prime is 2114350534099. The next prime is 2114350534123. The reversal of 2114350534113 is 3114350534112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2114350534113 - 2⁹ = 2114350533601 is a prime.

It is a super-2 number, since 2×2114350534113² (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (2114350534123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352391755683 + ... + 352391755688.

It is an arithmetic number, because the mean of its divisors is an integer number (704783511372).

Almost surely, 2^{2114350534113} is an apocalyptic number.

It is an amenable number.

2114350534113 is a deficient number, since it is larger than the sum of its proper divisors (704783511375).

2114350534113 is an equidigital number, since it uses as much as digits as its factorization.

2114350534113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 704783511374.

The product of its (nonzero) digits is 21600, while the sum is 33.

Subtracting 2114350534113 from its reverse (3114350534112), we obtain a palindrome (999999999999).

The spelling of 2114350534113 in words is "two trillion, one hundred fourteen billion, three hundred fifty million, five hundred thirty-four thousand, one hundred thirteen".